| Answer
to 2c. |
|
|
|
|
|
|
|
|
| n | At the 0 volume
point, no acid has been |
||||||
| added. Thus the
concentration of the base |
|||||||
| is unchanged from
the original. |
|||||||
| n | Because
CN- is a weak base, we must |
||||||
| calculate its pOH
using the Kb reaction |
|||||||
| n | CN-(aq)
+ H2O(l) HCNaq) + OH-(aq) |
||||||
| 3 |
| ξ |
| 0 |
| 0 |
| -x |
| -x |
| +x |
| +x |
| 3-x |
| ξ |
| x |
| x |
